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This lesson is divided into three sections,
all dealing with angles formed by intersections outside of the circle.
Section 1: Angle formed by two tangents
Section 2: Angles formed by two secants
Section 3: Angle formed by a tangent and a secant |
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The formulas for all THREE of these situations are the same: |
Angle Formed Outside = (DIFFERENCE of Intercepted Arcs) |
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These differences always yield a positive result. (larger arc subtract smaller arc)
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An angle formed by two tangents is an angle created when two tangent lines to the circle intersect at a point outside of the circle. |
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Angle formed by Two Tangents: |
∠ ABC is formed by two tangents intersecting outside of circle O.
The intercepted arcs are arc minor and major arc .
These two arcs together comprise the entire circle.
Angle Formed by Two Tangents
= (DIFFERENCE of Intercepted Arcs)
(When subtracting, start with the larger arc.)
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m∠ABC = 60º |
Note: When dealing with two tangents, you are dealing with the ENTIRE circle (360º). This will not be the case in the next two sections. |
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Note:
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It can be proven that:
∠ABC and central angle ∠AOC are supplementary (add up 180º).
Also, the angle formed by the two tangents and the first minor intercepted are also supplementary
(add to 180º). |
This supplementary association will NOT apply to Two Secants, nor to Tangent-Secant diagrams.
Example 1:
Given two tangents, find x.
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Solution:
• Since the major arc is 230º. the minor arc is
360 - 230 = 130º.
• The angle x will be half the difference of the two intercepted arcs.
• x = ½ (230 - 130) = ½ (100) = 50º*
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Example 2:
Given two tangents, with m∠C = 65º.
Find the number of degrees in the minor arc from point A to point B.
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Solution:
• If you remember the "note" from above, you remember that ∠C and its minor arc are supplementary. (180 - 65 = 115)
Thus the minor arc has a measure of 115º*.
• If you forget the "note", you can still solve this problem algebraically with the formula.
Let minor arc = x. and let major arc = 360 - x.
Apply the formula: 65 = ½ (360-x - x)
65 = ½ (360 - 2x)
130 = 360 - 2x
2x = 230
x = 115º*
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PROOF: Angle formed by Two Tangents
For ease of reading,
let m∠1 = m∠ AED
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An angle formed by two secants is an angle created when two secant lines through a circle intersect at a point outside of the circle. |
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Angle formed by Two Secants: |
∠ CAE is formed by two secants intersecting outside of circle O at point A.
The intercepted arcs are arc and arc .
Angle Formed by Two Secants
= (DIFFERENCE of Intercepted Arcs)
(When subtracting, start with the larger arc.)
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While the tangent-tangent angle utilized the entire circle, the secant-secant angle will only use the portions of the circle that fall between the secant lines. |
m∠CAE = 35º
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Example 1:
Given two secants, with one secant passing through the center of the circle.
Find x.
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Solution:
• Since one secant is passing through the center, we are dealing with a semicircle (180º).
On the top half of the circle, we have
25º + 75º + ? = 180º. The missing top arc is 80º.
• Apply the formula: x = ½ (80 - 25)
• x = ½ (55) = 27½º*
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Example 2:
Given two secants, find x.
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Solution:
• Apply the formula: 2x = ½ (7x + 15 - 45)
• Solve for x:
2x = ½ (7x + 15 - 45)
2x = ½ (7x - 30)
4x = 7x - 30
30 = 3x
10 = x*
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PROOF: Angle formed by Two Secants
SECTION 3: Tangent-Secant: |
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An angle formed by one tangent and one secant is an angle created when a secant lines passes through a circle intersects outside the circle with a line tangent to the circle. |
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Angle formed by a Tangent and a Secant: |
∠ BAD is formed by a tangent and a secant intersecting outside of circle O.
The intercepted arcs are arc and arc .
Angle Formed by Tangent and Secant
= (DIFFERENCE of Intercepted Arcs)
(When subtracting, start with the larger arc.)
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Like the secant-secant angle, the tangent-secant angle utilizes only portions of the circle that fall between the secant and tangent lines. |
m∠BAD = 47º
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Example 1:
Given a secant and a tangent.
Find x. |
Solution:
• We are missing an arc needed for the formula.
Since the circle totals 360º, we can find the missing arc: 360 - (235 + 45) = missing arc.
Missing arc = 80º
• Apply the formula: x = ½ (80 - 45)
• x = ½ (80 - 45)
x = ½ (35)
x = 17½º*
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Example 2:
Given a secant and a tangent.
Find x.
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Solution:
• Apply the formula: 45 = ½(165 - x)
Be sure to subtract the smaller arc from the larger arc.
• Solve for x:
45 = ½(165 - x)
90 = 165 - x
x = 75º*
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PROOF: Angle formed by one Secant and one Tangent:
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• Again, note the similarity in the three proofs from this lesson.
They all follow the same pattern, with adjustments for the diagrams.
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